Theorem 2: Number of permutations of n different objects taken r at a time, where repetition is allowed, is nr.
Numerical: Find 3 digit numbers formed from (1,3,5,7,9) when repetition is allowed

Solution: let’s solve using logical method. Since 3 digit numbers has to be formed, lets assume 3 buckets
In this case, bucket 1 can have any of the 5 digits (1,3,5,7,9). That is 5 choices
Bucket 2 can also have any of the 5 digits, since repetition is allowed, that is 5 choices
Bucket 3 can also have any of the 4 digits, since repetition is allowed, that is 5 choices
So, total number of 3 digit numbers with repetition is 5 * 5 * 5 = 125
Lets solve using formula.
Total number of 3 digit numbers with repetition is nr , here n=5 & r =3
So, Total number of 3 digit numbers with repetition 53 = 125
ExamFear recommends the conventional logical way to solve Probability questions.
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