NCERT Solutions
Class 9 Maths
Quadrilaterals

Ex.8.1 Q.3
Show that if the diagonals of a quadrilateral bisect each other at right angles, then it is a rhombus.
Let ABCD be a quadrilateral, whose diagonals AC and BD bisect each other at right angle i.e.,
OA = OC, OB = OD, and ∠AOB = ∠BOC = ∠COD = ∠AOD = 900.
To prove, ABCD a rhombus, we have to prove ABCD is a parallelogram and all the sides of ABCD are equal.
In ΔAOD and ΔCOD,
OA = OC
(Diagonals bisect each other)
∠AOD = ∠COD
(Given)
OD = OD
(Common)
So, ΔAOD ≅ ΔCOD (By SAS congruence rule)
Hence, AD = CD …………... (1)
Similarly, it can be proved that
AD = AB and CD = BC ………... (2)
From equation (1) and (2), we get
AB = BC = CD = AD
Since opposite sides of quadrilateral ABCD are equal,
it can be said that ABCD is a parallelogram.
Since all sides of a parallelogram ABCD are equal, it can be said that ABCD is a rhombus.