NCERT Solutions
Class 9 Maths
Polynomials

Ex.2.2 Q.3
Verify whether the following are zeroes of the polynomial, indicated against them.
(1) p(x) = 3x + 1, x = -
(2) p(x) = 5x – π, x =
(3) p(x) = x2 – 1, x = 1, –1
(4) p(x) = (x + 1) (x – 2), x = – 1, 2
(5) p(x) = x2, x = 0
(6) p(x) = lx + m, x = -
(7) p(x) = 3x2 - 1, x = - ,
(8) p(x) = 2x + 1, x =
(1) Put x = - , we get
p (-13 ) = 3 × (-
) + 1 = -1 + 1 = 0
Hence, x = - is a zero of the polynomial p(x) = 3x + 1
(2) put x = , we get
p(x) = 5 × – π = 4 – π
Hence, x = 4/5 is a zero of the polynomial p(x) = 5x – π
(3) Put x = 1, we get
p (1) = 12 – 1 = 1 – 1 = 0
Hence, x = 1 is a zero of the polynomial p(x) = x2 – 1
Put x = -1, we get
p (1) = (-1)2 – 1 = 1 – 1 = 0
Hence, x = -1 is a zero of the polynomial p(x) = x2 – 1
(4) Put x = -1, we get
p (-1) = (-1 + 1) (-1 – 2) = 0 × (-3) = 0
Hence, x = -1 is a zero of the polynomial p(x) = (x + 1) (x - 2)
Put x = 2, we get
p (2) = (2 + 1) (2 – 2) = 3 × 0 = 0
Hence, x = 2 is a zero of the polynomial p(x) = (x + 1) (x - 2)
(5) p(x) = x2, x = 0
Put x = 0, we get
p (0) = 02 = 0
Hence, x = 0 is a zero of the polynomial p(x) = x2
(6) Put x = - , we get
p (- ) = l × (-
) + m = -m + m = 0
Hence, x = - is a zero of the polynomial p(x) = lx + m
(7) Put x = - , we get
p (- ) = 3 × (-
)2 – 1 = 3 ×
– 1 = 1 – 1 = 0
Hence, x = - is a zero of the polynomial 3x2 – 1.
Put x = , we get
p ( ) = 3 × (
)2 – 1 = 3 ×
– 1 = 4 – 1 = 3.
It is not equal to zero. Hence, x = 2/√3 is not a zero of the polynomial 3x2 – 1.
(8) Put x = , we get
p ( ) = 2 × (
) + 1 = 1 + 1 = 2
It is not equal to zero. Hence, x = is not a zero of the polynomial 2x + 1.