NCERT Solutions
Class 9 Maths
Constructions

Ex.11.1 Q.1
Construct an angle of 900 at the initial point of a given ray and justify the construction.
Steps of Construction:
1. Let us take a ray AB with initial point A.
2. Taking A as centre and some radius, draw an arc of a circle, which intersects AB at C.
3. With C as centre and the same radius as before, draw an arc, intersecting the previous arc at E.
4. With E as centre and the same radius, as before, draw an arc, which intersects the arc drawn in step 2 at F.
5. With E as centre and some radius, draw an arc.
6. With F as centre and the same radius as before, draw another arc, intersecting the previous arc at G.
7. Draw the ray AG.
Then BAG is the required angle of 900.
Justification: Join AE, CE, EF, FG and GE
AC = CE = AE
[By construction]
ΔACE is an equilateral triangle
Angle CAE = 60°...……...……… (1)
Similarly, ΔAEF = 60………... (2)
From (i) and (ii), FE || AC …. (3)
[Alternate angles are equal]
Also, FG = EG
[By construction]
=> G lies on the perpendicular bisector of EF in angle GIE = 900 ... (4)
So, angle GAB = angle GIE = 900
[Corresponding angles]
GF = GE
[Arcs of equal radii]