NCERT solution Class 8 squares and square roots

NCERT Solutions

Class 8 Maths

Squares and Square Roots

NCERT Questions

Ex.6.1 Q.1
Ex.6.1 Q.2
Ex.6.1 Q.3
Ex.6.1 Q.4
Ex.6.1 Q.5
Ex.6.1 Q.6
Ex.6.1 Q.7
Ex.6.1 Q.8
Ex.6.1 Q.9
Ex.6.2 Q.1
Ex.6.2 Q.2
Ex.6.3 Q.1
Ex.6.3 Q.2
Ex.6.3 Q.3
Ex.6.3 Q.4
Ex.6.3 Q.5
Ex.6.3 Q.6
Ex.6.3 Q.7
Ex.6.3 Q.8
Ex.6.3 Q.9
Ex.6.3 Q.10
Ex.6.4 Q.1
Ex.6.4 Q.2
Ex.6.4 Q.3
Ex.6.4 Q.4
Ex.6.4 Q.5
Ex.6.4 Q.6
Ex.6.4 Q.7
Ex.6.4 Q.8
Ex.6.4 Q.9

Ex.6.2 Q.2

Write a Pythagoras triplet whose one member is:

1. 6

2. 14

3. 16

4. 18

1. There are three numbers 2m, m² – 1 and m² + 1 in a Pythagorean triplet.

Here, 2m = 6 => m = 6 ÷ 2 = 3

Therefore, second number is:

m² – 1 = 3² – 1 = 9 – 1 = 8

Third Number is:

m² + 1 = 3² + 1 = 9 + 1 = 10

Hence, Pythagorean triplet is (6, 8, 10)

2. There are three numbers 2m, m² – 1 and m² + 1 in a Pythagorean triplet.

Here, 2m = 14 => m = 14 ÷ 2 = 7

Therefore, second number is:

m² – 1 = 7² – 1 = 49 – 1 = 48

Third Number is:

m² + 1 = 7² + 1 = 49 + 1 = 50

Hence, Pythagorean triplet is (14, 48, 50)

3. There are three numbers 2m, m² – 1 and m² + 1 in a Pythagorean triplet.

Here, 2m = 16 => m = 16 ÷ 2 = 8

Therefore, second number is:

m² – 1 = 8² – 1 = 64 – 1 = 63

Third Number is:

m² + 1 = 8² + 1 = 64 + 1 = 65

Hence, Pythagorean triplet is (16, 63, 65)

4There are three numbers 2m, m² – 1 and m² + 1 in a Pythagorean triplet.

Here, 2m = 18 => m = 18 ÷ 2 = 9

Therefore, second number is:

m² – 1 = 9² – 1 = 81 – 1 = 80

Third Number is:

m² + 1 = 9² + 1 = 81 + 1 = 82

Hence, Pythagorean triplet is (9, 80, 82)

Video solution:

Squares and Square Roots Class 8 Maths NCERT Chapter 6 NCERT Solutions

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NCERT solutions of Squares and Square Roots Class 8 Maths - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 8 Maths Squares and Square Roots NCERT solutions.