NCERT Solutions
Class 8 Maths
Squares and Square Roots

Ex.6.4 Q.4
Find the least number which must be subtracted from each of the following numbers so as to get a perfect square.
Also, find the square root of the perfect square so obtained:
1. 402
2. 1989
3. 3250
4. 825
5. 4000
1. 402
We know that, if we subtract the remainder from the
number, we get a perfect square.
Here, we get remainder 2. Therefore 2 must be
subtracted from 402 to get a perfect square.
So, 402 – 2 = 400
Hence, the square root of 400 is 20.
2. 1989
We know that, if we subtract the remainder from the
number, we get a perfect square.
Here, we get remainder 53. Therefore 53 must be
subtracted from 1989 to get a perfect square.
So, 1989 – 53 = 1936
Hence, the square root of 1936 is 44.
3. 3250
We know that, if we subtract the remainder from the
number, we get a perfect square.
Here, we get remainder 1. Therefore 1 must be
subtracted from 3250 to get a perfect square.
So, 3250 – 1 = 3249
Hence, the square root of 3249 is 57.
4. 825
We know that, if we subtract the remainder from the
number, we get a perfect square.
Here, we get remainder 41. Therefore 41 must be
subtracted from 825 to get a perfect square.
So, 825 – 41 = 784
Hence, the square root of 784 is 28.
5. 4000
We know that, if we subtract the remainder from the
number, we get a perfect square.
Here, we get remainder 31. Therefore 31 must be
subtracted from 4000 to get a perfect square.
So, 4000 – 31 = 3969
Hence, the square root of 3969 is 63.