NCERT Solutions
Class 8 Maths
Factorisation

Ex.14.2 Q.2
Factorize:
1. 4p2 – 9q2
2. 63a2 – 112b2
3. 9x2 – 36 4. 16x5 – 144x2
5. (l + m)2 – (l - m)2
6. 9x2 y2 – 16
7. (x2 – 2xy + y2) – z2
8. 25a2 – 4b2 + 28bc – 49c2
1. 4p2 – 9q2 = (2p)2 – (3q)2
= (2p – 3q) (2p + 3q)
[a2 – b2 = (a - b) (a + b)]
2. 63a2 – 112b2 = 7(9a2 – 16b2)
= 7{(3a)2 – (4b)2}
= 7(3a – 4b) (3a + 4b)
[a2 – b2 = (a - b) (a + b)]
3. 49x2 – 36 = (7x)2 – 62
= (7x - 6) (7x + 6)
[a2 – b2 = (a - b) (a + b)]
4. 16x5 – 144x2 = 16x3 (x2 – 9)
= 16x3 (x2 – 32)
= 16x3 (x – 3) (x + 3)
[a2 – b2 = (a - b) (a + b)]
5. (l + m)2 – (l - m)2 = l2 + 2lm + m2 – (l2 – 2lm + m2)
= l2 + 2lm + m2 – l2 + 2lm - m2
= 4lm
6. 9x2 y2 – 16 = (3xy)2 – 42
= (3xy - 4) (3xy + 4)
[a2 – b2 = (a - b) (a + b)]
7. (x2 – 2xy + y2) – z2 = (x - y)2 – z2
= (x – y + z) (x – y - z)
[a2 – b2 = (a - b) (a + b)]
8. 25a2 – 4b2 + 28bc – 49c2 = 25a2 – (4b2 - 28bc + 49c2)
= 25a2 – {(2b)2 – 2 × 2b × 7c + (7c)2}
= (5a)2 – (2b – 7c)2
= {5a - (2b – 7c)} (5a + 2b – 7c)
= {5a - 2b + 7c) (5a + 2b – 7c)