NCERT solution Class 8 comparing quantities

NCERT Solutions

Class 8 Maths

Comparing Quantities

NCERT Questions

Ex.8.1 Q.1
Ex8.1 Q.2
Ex.8.1 Q.3
Ex.8.1 Q.4
Ex.8.1 Q.5
Ex.8.1 Q.6
Ex.8.2 Q.1
Ex.8.2 Q.2
Ex.8.2 Q.3
Ex.8.2 Q.4
Ex.8.2 Q.5
Ex.8.2 Q.6
Ex.8.2 Q.7
Ex.8.2 Q.8
Ex.8.2 Q.9
Ex.8.2 Q.10
Ex.8.2 Q.11
Ex.8.3 Q.1
Ex.8.3 Q.2
Ex.8.3 Q.3
Ex.8.3 Q.4
Ex.8.3 Q.5
Ex.8.3 Q.6
Ex.8.3Q.7
Ex.8.3 Q.8
Ex.8.3 Q.9
Ex.8.3 Q.10
Ex.8.3 Q.11
Ex.8.3 Q.12

Ex.8.3 Q.8

Find the amount and the compound interest on Rs 10,000 for 112 years at 10% per annum,

compounded half yearly.

Would this interest be more than the interest he would get if it was compounded annually?

Here,

Principal (P) = Rs 10000, Rate of Interest (R) = 10% = 5% (compounded half yearly)

Time (n) = 1 years = 3 half-years (compounded half yearly)

Amount (A) = P (1 + )ⁿ

= 10000(1 + )³

= 10000( )³

= 10000 × × ×

= Rs 11,576.25

Compound Interest (C.I.) = A – P = Rs 11,576.25 – Rs 10,000 = Rs 1,576.25

If it is compounded annually, then

Here, Principal (P) = Rs 10000, Rate of Interest (R) = 10%, Time (n) = 1 years

Amount (A) for 1 year = P (1 + )ⁿ

= 10000(1 + )¹

= 10000( )¹

= 10000 ×

= Rs 11000

Interest for year = (11000 × 1 × 10) ÷ (2 × 100) = 110 × 5 = Rs 550

Total amount = Rs 11,000 + Rs 550 = Rs 11,550

Now, C.I. = A – P = Rs 11,550 – Rs 10,000 = Rs 1,550

Yes, interest Rs 1,576.25 is more than Rs 1,550.

Video solution:

Comparing Quantities Class 8 Maths NCERT Chapter 8 NCERT Solutions

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NCERT solutions of Comparing Quantities Class 8 Maths - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 8 Maths Comparing Quantities NCERT solutions.