NCERT solution Class 7 comparing quantities

NCERT Solutions

Class 7 Maths

Comparing Quantities

NCERT Questions

Ex.8.1 Q.1
Ex.8.1 Q.2
Ex.8.1 Q.3
Ex.8.2 Q.1
Ex.8.2 Q.2
Ex.8.2 Q.3
Ex.8.2 Q.4
Ex.8.2 Q.5
Ex.8.2 Q.6
Ex.8.2 Q.7
Ex.8.2 Q.8
Ex.8.2 Q.9
Ex.8.2 Q.10
Ex.8.3 Q.1
Ex.8.3 Q.2
Ex.8.3 Q.3
Ex.8.3 Q.4
Ex.8.2 Q.5
Ex.8.3 Q.6
Ex.8.3 Q.7
Ex.8.3 Q.8
Ex.8.3 Q.9
Ex.8.3 Q.10
Ex.8.3 Q.11

Ex.8.3 Q.1

Tell what is the profit or loss in the following transactions.

Also find profit percent or loss percent in each case.

(a) Gardening shears bought for ₹ 250 and sold for ₹ 325.

(b) A refrigerator bought ₹12,000 and sold at ₹ 13,500.

(d) A skirt bought for ₹ 250 and sold at ₹ 150.

(a) Cost price of gardening shears = ₹ 250

Selling price of gardening shears = ₹ 325

Since, S.P. > C.P., therefore here is profit.

So, Profit = S.P. – C.P. = ₹325 – ₹250 = ₹ 75

Now Profit% = * 100

= * 100

= 3 * 10

= 30%

Therefore, Profit = ₹75 and Profit% = 30%

(b) Cost price of refrigerator = ₹ 12,000

Selling price of refrigerator = ₹13,500

Since, S.P. > C.P., therefore here is profit.

So, Profit = S.P. – C.P. = ₹13500 – ₹12000 = ₹1,500

Now Profit% = * 100

= * 100

= 12.5%

Therefore, Profit = ₹1,500 and Profit% = 12.5%

Selling price of cupboard = ₹ 3,000

Since, S.P. > C.P., therefore here is profit.

So, Profit = S.P. – C.P. = ₹3,000 – ₹2,500 = ₹ 500

Now Profit% = * 100

= * 100

= 20%

Therefore, Profit = ₹ 500 and Profit% = 20%

(d) Cost price of skirt = ₹ 250

Selling price of skirt = ₹ 150

Since, C.P. > S.P., therefore here is loss.

So, Loss = C.P. – S.P. =₹250 – ₹150 = ₹100

Now Loss% = * 100

= * 100

= 2 * 10

= 40%

Therefore, Profit = ₹ 100 and Profit% = 40%

Video solution:

Comparing Quantities Class 7 Maths NCERT Chapter 8 NCERT Solutions

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NCERT solutions of Comparing Quantities Class 7 Maths - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 7 Maths Comparing Quantities NCERT solutions.