NCERT solution Class 12 electrochemistry

NCERT Solutions

Class 12 Chemistry

Electrochemistry

NCERT Questions

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Q.17

Using the standard electrode potentials given in Table 3.1, predict if the reaction between the following is feasible:

(i) Fe³⁺(aq) and I^–(aq)

(ii) Ag⁺ (aq) and Cu(s)

(iii) Fe³⁺ (aq) and Br^– (aq)

(iv) Ag(s) and Fe ³⁺ (aq)

(v) Br^{^[1]} (aq) and Fe^{^[2]}⁺ (aq).

[1] Ag⁺ (aq) + Cu(s) à 2Ag(s) + Cu²⁺ (aq); E⁰ = +0.46

Since for the overall reaction is positive, the reaction between Ag ⁺ (aq) and Cu(s) is feasible.

(iii) Fe³⁺ (aq) + e^- à Fe²⁺ (aq)] x2; E⁰ =+0.77 V

[2] Br^- à Br₂(s) + 2e^-; E⁰ =-1.09 V

(i) Fe³⁺ (aq) + e^- à Fe²⁺ (aq)] x2; E⁰ =+0.77 V

2I^- à I₂(s) + 2e^-; E⁰ =-0.54 V

2Fe³⁺ (aq) +2I^-(aq) à 2Fe²⁺ (aq) + I₂(s); E⁰ = +0.23 V

Since E⁰ for the overall reaction is positive, the reaction between Fe ³⁺ (aq) and I⁻ (aq) is feasible.

(ii) Ag⁺(aq) + e^- à Ag(s) ] x2 ; E⁰ = +0.80V

Cu(s) à Cu²⁺ (aq) +2e- ; E⁰ = -0.34 V

2Fe³⁺ (aq) +2Br^-(aq)  2Fe²⁺ (aq) + Br₂(s); E⁰ = -0.32 V

Since E⁰ for the overall reaction is positive, the reaction between Fe ³⁺ (aq) and Br⁻ (aq) is feasible.

(iv) Ag (s) à Ag⁺(aq) + e^-; E⁰ = -0.80V

Fe³⁺ (aq) + e^- à Fe²⁺ (aq); E⁰ =+0.77 V

Ag(s) + Fe³⁺ (aq) à Ag⁺ (aq) +Fe²⁺ (aq); E⁰ =-0.03 V

Since E for the overall reaction is negative, the reaction between Ag (s) and Fe³⁺ (aq) is not feasible.

(v) 2Br^- + 2e^- à Br₂^-; E⁰ =+1.09 V

2Fe³⁺ (aq) à Fe³⁺ (aq) + e^-] x 2; E⁰ = -0.77V

[1] Ag⁺ (aq) + Cu(s) à 2Ag(s) + Cu²⁺ (aq); E⁰ = +0.46

Since for the overall reaction is positive, the reaction between Ag ⁺ (aq) and Cu(s) is feasible.

(iii) Fe³⁺ (aq) + e^- à Fe²⁺ (aq)] x2; E⁰ =+0.77 V

[1] Br^- à Br₂(s) + 2e^-; E⁰ =-1.09 V

Since for the overall reaction is positive, the reaction between Br₂ (aq) and Fe²⁺ (aq) is feasible.

Video solution:

Electrochemistry Class 12 Chemistry NCERT Chapter 2 NCERT Solutions

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