NCERT Solutions
Class 12 Chemistry
Electrochemistry

Q.3
Depict the galvanic cell in which the reaction
Zn(s) +2Ag+ (aq) →Zn2+ (aq) +2Ag(s) take place. Further show:
(i) Which of the electrode is negatively charged?
(ii) The carriers of the current in the cell.
(iii) Individual reaction at each electrode.
The galvanic cell corresponding to the given redox reaction can be represented as:
Zn | Zn2+ (aq) || Ag+ (aq) | Ag
(i) Zn electrode is negatively charged because at this electrode, Zn oxidizes to Zn2+ and the leaving electrons accumulate on this electrode.
(ii) Ions are the carriers of current in the cell.
(iii) The reaction taking place at Zn electrode can be represented as:
Zn(s) à Zn2+ (aq) + 2e-
And the reaction taking place at Ag electrode can be represented as:
Ag+ (aq) + e- àAg(s)
(iv) In aqueous solutions, CuCl 2 ionizes to give Cu2+ and Cl– ions as:
CuCl2 (aq) à Cu2+ (aq) +2Cl-(aq)
On electrolysis, either of Cu2+ ions or H2O molecules can get reduced at the cathode. But the reduction potential of Cu 2+ is more than that of H 2O molecules.
Cu2+ (aq) + 2e- àCu (aq); E0= +0.34V
H2O (l) +2e- àH2 (g) +2OH- ; E0=-0.83 V
Hence, Cu2+ ions are reduced at the cathode and get deposited.
Similarly, at the anode, either of Cl – or H2O is oxidized. The oxidation potential of H2O is higher than that of Cl–.
2Cl-(aq) à Cl2 (g) + 2e- ; E0= -1.36V
2H2O (l) à O2 (g) +4H- + 4e-; E0=-1.23 V
But oxidation of H2O molecules occurs at a lower electrode potential than that of Cl– ions because of over-voltage (extra voltage required to liberate gas). As a result, Cl– ions are oxidized at the anode to liberate Cl 2 gas.