NCERT Solutions

Class 12 Chemistry

Amines

learnohub

Q.5

How will you convert?

(i) Ethanoic acid into Methanamine

(ii) Hexanenitrile into 1-aminopentane

(iii) Methanol to ethanoic acid

(iv) Ethanamine into Methanamine

(v) Ethanoic acid into propanoic acid

(vi) Methanamine into Ethanamine

(vii) Nitromethane into dimethylamine

(viii) Propanoic acid into ethanoic acid?

(i) Ethanoic acid into Methanamine

 

To convert ethanoic acid into methanamine (CH 3NH2), we need ethanamide (amide group-RCONH2) and we can get ethanamide from ethanoyl chloride (acid chloride group- RCOCl).

Step-1: Convert ethanoic acid into ethanoyl chloride

Ethanoic acid (CH3COOH) reacts with thionyl chloride (SOCl 2) or PCl5 or PCl3 to form ethanoyl chloride (CH 3COCl) by the replacement of OH group by Cl atom.

 

Step-2 Convert ethanoyl chloride into ethanamide

Ethanoyl chloride (CH3COCl) reacts with ammonia (in excess) to form ethanamide (CH3CONH2) by removal of NH4Cl

 

Step-3: Convert ethanamide into methanamine (Hoffman Bromamide reaction) Ethanamide (CH3CONH2) is treated with an aqueous or ethanolic solution of potassium hydroxide (KOH) and bromine (Br 2); it gives ethanamine (CH 3NH2-final product)

 

Note: Hoffman Bromamide Reaction is a reaction in which a primary amide is treated with an aqueous KOH or NaOH and bromine; it gives a primary amine which has one carbon atom less than the original amide.

(ii) Hexanenitrile into 1-aminopentane

  

The structure of Hexanenitrile is CH 3CH2CH2CH2CH2CN or C5H11CN. To convert

Hexanenitrile into 1-aminopentane, first we need hexanamide (amide groupRCONH2) and we can get hexanamide from hexanoyl chloride (acid chloride group – RCOCl) and we can get hexanoyl chloride from hexanoic acid.

 

Step 1: Convert Hexanenitrile into Hexanoic acid

Hexanenitrile (C5H11CN) undergoes hydrolysis to form Hexanoic acid

(C5H11COOH)

 

Step 2: Convert Hexanoic acid into hexanoyl chloride

Hexanoic acid (C5H11COOH) reacts with thionyl chloride (SOCl 2) or PCl5 or PCl3 to form hexanoyl chloride (C5H11COCl) by the replacement of OH group by Cl atom.

 

Step 3: Convert Hexanoyl chloride into hexanamide

Hexanoyl chloride (C5H11COCl) reacts with excess ammonia to form hexanamide (C5H11CONH2) by the removal of NH 4Cl.

 

Step 4: Convert hexanamide into 1- amino pentane by Hoffman Bromamide reaction)

Hexanamide (C5H11CONH2) is treated with an aqueous or ethanolic solution of potassium hydroxide (KOH) and bromine (Br 2), it gives 1-aminopentane (final product) which has one carbon atom less than the hexanamide.

         

(iii) Methanol to ethanoic acid

 

The structure of methanol is CH 3OH. To convert methanol to ethanoic acid (the number of carbon atoms is increasing from one carbon atom to two carbon atoms) we need ethanenitrile and we can get ethanenitrile from methyl chloride.

Note: If the number of carbon atoms is increasing, we need a nitrile group and if the number of atoms is decreasing, we need an amide group (Hoffman Bromamide reaction)

 

Step 1: Convert methanol into methyl chloride

Methanol (CH3OH) reacts with thionyl chloride (SOCl 2) or PCl5 or PCl3 to form methyl chloride (CH3Cl) by the replacement of OH group by Cl atom.

 

Step 2: Convert methyl chloride into ethanenitrile

Methyl chloride (CH3Cl) reacts with ethanolic NaCN/ KCN to form ethanenitrile (CH3CN) by the removal of NaCl / KCl

 

Step 3: Convert ethanenitrile into ethanoic acid

Ethanenitrile (CH3CN) undergoes hydrolysis to form ethanoic acid (final product) which has one carbon atom more than the ethanenitrile

         

(iv) Ethanamine into Methanamine

 

The structure of ethanamine is CH 3CH2NH2. To convert ethanamine into methanamine (the number of carbon atoms is decreasing from two carbon atoms to one carbon atom), first we need ethanamide (amide group- RCONH2) and we can get acetamide from acetic acid. By oxidation of ethanol, we can get ethanoic acid.

 

Step 1: Convert Ethanamine into ethanol with the help of diazonium salt

Ethanamine (CH3CH2NH2) reacts with NaNO2 and HCl to give Diazonium salt

(R-N2+Cl-) which undergoes hydrolysis to form ethanol.

Note: The diazonium salts or diazonium compounds are the class of organic compounds with general formula R−N 2+X where X is an organic or inorganic anion (for example, Cl–, Br–, BF4, etc.) and R is an alkyl or aryl group. Hence, they have two nitrogen atoms with one being charged. Example -

Benzenediazonium chloride (C6H5N2+Cl)

 

 

Step 2: Convert ethanol to ethanoic acid by oxidation

Ethanol (CH3CH2OH) undergoes oxidation in the presence of strong oxidizing agent KMNO4 to form ethanoic acid (CH 3COOH)

 

Step 3: Convert ethanoic acid into ethanamide (amide group)

Ethanoic acid (CH3COOH) is treated with ammonia (in excess) to form ethanamide (CH3CONH2)

 

Step 4: Convert ethanamide into methanamine by Hoffman Bromamide Reaction

Ethanamide (CH3CONH2) is treated with alcoholic NaOH or KOH in the presence of bromine; it gives methanamine (CH 3NH2 - final product) which has one carbon atom less than the ethanamide.

        

(v) Ethanoic acid into propanoic acid

 

To convert ethanoic acid into propanoic acid (the number of carbon atoms is increasing from two carbon atoms to three carbon atoms), we need propionitrile (CH3CH2CN) and we can get propionitrile from ethyl chloride. To get ethyl chloride, we need ethanol which can be formed by the reduction of ethanoic acid.

 

Step 1: Convert ethanoic acid into ethanol by reduction

Ethanoic acid (CH3COOH) undergoes reduction in the presence of lithium aluminium hydride (LiAlH4) to form ethanol (CH 3CH2OH)

 

Step 2: Convert ethanol into ethyl chloride

Ethanol (CH3CH2OH) reacts with PCl5 to form ethyl chloride (CH 3CH2Cl) by the replacement of OH group by Cl atom.

 

Step 3: Convert ethyl chloride into ethyl cyanide/ propionitrile

Ethyl chloride (CH3CH2Cl) reacts with ethanolic NaCN / KCN to give ethyl cyanide/ propionitrile (CH 3CH2CN)

 

Step 4: Convert ethyl cyanide/ propionitrile into propanoic acid

Ethyl cyanide (CH3CH2CN) undergoes hydrolysis to form a propanoic acid (CH3CH2COOH-final product) which has one carbon atom more than the propionitrile.

         

(vi) Methanamine into Ethanamine

 

The structure of methanamine is CH 3NH2 and the structure of ethanamine is CH3CH2NH2. To convert methanamine into ethanamine (the number of carbon atoms are increasing from one carbon atom two carbon atoms) so we need ethanenitrile which we can get from ethyl chloride. We can obtain ethyl chloride from alcohol which can be obtained from diazonium salt (R--N2+Cl-)

 

Step 1: Convert methyl amine to methanol

Methyl amine (CH3NH2) is first treated with HNO2 and HCl, which gives a fresh diazonium salt (R--N2+Cl-) and then diazonium salt undergoes hydrolysis to form methanol.

 

Step 2: Convert methanol to methyl chloride

Methanol is treated with PCl 5 or thionyl chloride, gives ethanenitrile (CH 3Cl) by the replacement of OH atom by Cl atom.

 

Step 3: Convert methyl chloride to ethanenitrile

Methyl chloride (CH3Cl) is treated with ethanolic NaCN or KCN, gives ethanenitrile (CH3CN)

 

Step 4: Convert ethanenitrile to ethanamine

Ethanenitrile (CH3CN) undergoes a reduction in the presence of sodium and ethyl alcohol to form ethanamine (CH 3CH2NH2 – final product) which has one carbon atom more than the ethanenitrile.

          

(vii) Nitromethane into dimethylamine

 

The structure of Nitromethane is CH 3NO2 and structure of dimethylamine (CH3NHCH3), as dimethylamine is a secondary amine so to obtain this, methyl isocyanide (CH3NC) is required that can be obtained from methanamine through carbylamine reaction.

 

Step 1: Convert nitromethane to methanamine

Nitromethane (CH3NO2) undergoes reduction in the presence of Sn and HCl to form methanamine (CH 3NH2)

 

Step 2: Convert methanamine to methyl isocyanide by Carbylamine reaction

Methanamine (CH3NH2) is heated with alcoholic potassium hydroxide and chloroform, the methyl isocyanide (CH 3NC) is formed.

Note: Carbylamine reaction is given only by primary amines

Primary amines when heated with chloroform and alcoholic potassium hydroxide give isocyanides (carbylamines) having very unpleasant smell, which can be easily detected.

  R-NH2                     +   CHCl3      + 3KOH (alc.)         R-NC + 3KCl + H2O

Primary Amine      Chloroform   Potassium Hydroxide Carbylamine

 

Step 3: Convert methyl isocyanide to diethylamine

Methyl isocyanide (CH3NC) undergoes reduction in the presence of sodium and ethyl alcohol to form diethylamine (CH 3NHCH3-final product)

(viii) Propanoic acid into ethanoic acid

 The structure of propanoic acid is CH 3CH2COOH and the structure of ethanoic acid is CH3COOH. To convert propanoic acid to ethanoic acid (the number of carbon atoms are decreasing), we need propionamide (amide group-RCONH2). Then propionamide undergoes Hoffman Bromamide reaction to form methylamine. Then methylamine formed can be converted to ethanol to form ethanoic acid by oxidation.

 

Step 1: Convert propanoic acid to propionamide

Propanoic acid (CH3CH2COOH) reacts with ammonia (in excess) to form propionamide (CH3CH2CONH2)

 

Step 2: Convert propionamide to ethyl amine by Hoffman Bromamide reaction

Propionamide (CH3CH2CONH2) reacts with potassium hydroxide and bromine to form ethylamine (CH3CH2NH2) which has one carbon atom less than the propionamide (Hoffman Bromamide reaction)

 

Step 3: Convert ethyl amine to methanol by forming diazonium salt

Ethyl amine (CH3CH2NH2) reacts with NaNO2 and HCl to form diazonium salt

(R--N2+Cl-) then diazonium salt undergoes hydrolysis to from ethanol

(CH 3CH2OH)

Step 4: Convert ethanol to ethanoic acid by oxidation

Ethanol (CH3CH2OH) undergoes oxidation in the presence of strong oxidizing agent KMNO4 to form ethanoic acid (CH 3COOH-final product)

Video solution:

Amines Class 12 Chemistry NCERT Chapter 9 NCERT Solutions

Solving NCERT textbook questions of Amines Class 12 Chemistry NCERT Chapter 9 is a crucial step to gauge your understanding of the concepts. It provides you with an opportunity to assess your grasp of the material after learning each chapter. We have already provided solutions to all the exercises in the NCERT textbook of Class 12 Chemistry Amines, available in various formats such as video, text, and downloadable PDFs. If you need assistance with any of the NCERT questions or any other academic topics, feel free to ask in the “Ask Questions” section of LearnoHub.com.

Studying each and every line of the NCERT (National Council of Educational Research and Training) textbook of Amines Class 12 Chemistry and solving all the questions it contains can be highly beneficial for several reasons:

  1. Comprehensive Understanding: Class 12 Chemistry NCERT textbooks are designed by experts to provide a comprehensive understanding of the subject matter. By studying each line of Amines Class 12 Chemistry, you ensure that you don't miss any essential information or concepts.
  2. Strong Foundation: NCERT books form the foundation of many academic exams and competitive tests. Mastering these textbooks helps build a solid foundation of knowledge for higher-level studies.
  3. Clarity of Concepts: Solving the questions provided in NCERT textbooks for Amines Class 12 Chemistry NCERT Chapter 9 reinforces the concepts learned in each chapter. It helps you apply theoretical knowledge to practical problem-solving scenarios.
  4. Exam Preparation: Many standardized tests, including board exams and entrance exams, extensively rely on NCERT content. Familiarity with the textbook content and practice with its questions can enhance your exam performance.
  5. Common Language: NCERT textbooks use simple and easily understandable language. Mastering the material ensures you are well-versed in the language commonly used in various academic and competitive settings.
  6. Confidence Boost: Successfully solving all the NCERT questions of Amines Class 12 Chemistry gives you a sense of accomplishment and boosts your confidence in your knowledge and problem-solving skills.
  7. In-Depth Learning: Delving into each line of the textbook for the chapter Amines Class 12 Chemistry helps you gain in-depth knowledge of the subject, making you better prepared to tackle complex problems and real-life situations.
  8. Time Management: By thoroughly studying and solving all the NCERT questions, you develop efficient time management skills, which are crucial during exams when you need to answer questions within a limited time frame.
  9. Holistic Approach: NCERT textbooks usually cover a wide range of topics, providing a holistic understanding of the subject. This approach is essential for a well-rounded education.
  10. Application in Real Life: The concepts and knowledge gained from NCERT textbooks often have practical applications in everyday life, helping you make informed decisions and solve real-world challenges.

In conclusion, studying each line and solving all the questions of NCERT textbooks is an essential part of the learning process. It ensures a strong foundation, deep understanding, and overall academic growth.

How to make the most of NCERT Solutions module of Amines Class 12 Chemistry NCERT Chapter 9 on LearnoHub.com?

Using the NCERT solutions module effectively can significantly enhance your learning experience and understanding of the subject matter. Here's a step-by-step guide on how to make the most out of the NCERT solutions:

  1. Attempt to Solve Yourself: Before looking at the solution, try to solve or answer the question independently. This practice will help you test your knowledge and problem-solving skills.
  2. Match with Our Solution: After attempting the question, compare your result and approach with the provided NCERT solution. This step allows you to identify any mistakes or gaps in your understanding.
  3. Refer to Solution Video (if needed): If you encounter difficulty or are unable to solve a question, you can refer to the NCERT solution video on Amines Class 12 Chemistry NCERT Chapter 9 to get a step-by-step explanation of the correct approach. Pay attention to the reasoning and methodology used in the video.
  4. Solve Again Yourself: Once you've understood the solution, attempt to solve the question again by yourself. Repetition and practice solidify your understanding of the concepts and improve retention.
  5. Avoid Memorization: Focus on understanding the underlying principles and concepts behind each solution. Avoid simply memorizing the solutions, as this may hinder your ability to apply the knowledge in different contexts.
  6. Attempt All Questions: Make an effort to attempt all the questions provided in the NCERT textbook. This comprehensive practice will help you cover the entire syllabus and reinforce your understanding across various topics. You may refer Class 12 Chemistry Amines Online Test on LearnoHub.com.
  7. Review and Revise: Regularly review the concepts and solutions you've learned. Revise your notes and practice regularly to retain the knowledge effectively. You may refer Amines Class 12 Chemistry Notes.
  8. Ask for Clarification: If you encounter any doubts or have questions about the solutions, don't hesitate to seek clarification on the “Ask Questions” section of LearnoHub.com. Amines Class 12 Chemistry NCERT Chapter 9 Questions.

By following these steps and actively engaging with the NCERT solutions module of Class 12 Chemistry Amines NCERT Chapter 9, you can improve your learning outcomes, develop a better grasp of the subject, and perform well in exams and other academic assessments. Remember that consistent practice, understanding, and application of knowledge are key to academic success.

NCERT solutions of Amines Class 12 Chemistry - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 12 Chemistry Amines NCERT solutions.

Classes

  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • ICSE 6
  • ICSE 7
  • ICSE 8
  • ICSE 9
  • ICSE 10
  • NEET
  • JEE

YouTube Channels

  • LearnoHub Class 11,12
  • LearnoHub Class 9,10
  • LearnoHub Class 6,7,8
  • LearnoHub Kids

Overview

  • FAQs
  • Privacy Policy
  • Terms & Conditions
  • About Us
  • NGO School
  • Contribute
  • Jobs @ LearnoHub
  • Success Stories
© Learnohub 2026.