NCERT solution Class 11 work energy and power

NCERT Solutions

Class 11 Physics

Work Energy and Power

NCERT Questions

Q. 5.1
Q. 5.2
Q. 5.3
Q. 5.4
Q. 5.5
Q. 5.6
Q. 5.7
Q. 5.8
Q. 5.9
Q. 5.10
Q. 5.11
Q. 5.12
Q. 5.13
Q. 5.14
Q. 5.15
Q. 5.16
Q. 5.17
Q. 5.18
Q. 5.19
Q. 5.20
Q. 5.21
Q. 5.22
Q. 5.23

Q. 5.18

The bob of a pendulum is released from a horizontal position. If the length of the pendulum is 1.5 m, what is the speed with which the bob arrives at the lowermost point, given that it dissipated 5% of its initial energy against air resistance?

Given:

Length of the pendulum l =1.5m

Mass of the bob = m

Energy dissipated = 5%

According to the law of conservation of energy, the total energy of the system remains constant.

At the horizontal position:

Potential energy of the bob, E_P = mgl

Kinetic energy of the bob, E_K = 0

Total energy = mgl ... (i)

At the lowermost point (mean position):

Potential energy of the bob, E_P = 0

Kinetic energy of the bob, E_k = (1/2) mv²

Total energy = E_T = (1/2) mv²... (ii)

As the bob moves from the horizontal position to the lowermost point, 5% of its energy gets dissipated.

The total energy at the lowermost point is equal to 95% of the total energy at the horizontal point, i.e.

(1/2) mv² = (95/100) x mgl

v = √ (2x95x1.5x9.8)/ (100)

=5.285m/s

Video solution:

Work Energy and Power Class 11 Physics NCERT Chapter 5 NCERT Solutions

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NCERT solutions of Work Energy and Power Class 11 Physics - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 11 Physics Work Energy and Power NCERT solutions.