NCERT solution Class 11 waves

NCERT Solutions

Class 11 Physics

Waves

NCERT Questions

Q. 14.1
Q. 14.2
Q. 14.3
Q. 14.4
Q. 14.5
Q. 14.6
Q. 14.9
Q. 14.10
Q. 14.11
Q. 14.12
Q. 14.13
Q. 14.14
Q. 14.15
Q. 14.16
Q. 14.17
Q. 14.18
Q. 14.19

Q. 14.4

Use the formula v = (√ (γ P)/ρ) to explain why the speed of sound in air

(a) is independent of pressure,

(b) increases with temperature,

Given:

v = (√ (γ P)/ρ) … (i)

Where Density ρ = (Mass)/ (volume)

= (M/V) where M = Molecular weight of thee gas and V = volume of the gas.

Therefore equation (i) changes to,

v = (√ (γ PV)/ (M) … (ii)

Considering the ideal gas equation for n = 1:

PV = RT

For constant T, PV = Constant

Since both M and γ are constants, v = Constant

Hence, at a constant temperature, the speed of sound in a gaseous medium is independent of the change in the pressure of the gas.

Using:

v = (√ (γ P)/ρ) … (i)

For one mole of an ideal gas, the gas equation can be written as:

PV = RT

Or P = (RT)/ (V) ... (ii)

Substituting equation (ii) in equation (i), we get:

v = (√γ RT/V ρ)

= (√γRT/M) … (iv)

Where,

Mass, M = ρV is a constant, (γ and R) are also constants

We conclude from equation (iv) v √T

Hence, the speed of sound in a gas is directly proportional to the square root of the temperature of the gaseous medium, i.e., the speed of the sound increases with an increase in the temperature of the gaseous medium and vice versa.

Speed of sound in moist air = v_m

Speed of sound in dry air = v_d

Density of moist air = ρ_m

Density of dry air = ρ_d

Using:

v = (√ (γ P)/ρ)

Hence, the speed of sound in moist air is:

v_m = (√ (γ P)/ρ_m) …(i)

And the speed of sound in dry air is:

v_d = (√ (γ P)/ρ_d) …(ii)

On dividing equations (i) and (ii), we get:

(v_m/ v_d) = ((√γ P)/ ρ_m) x (√ (ρ_d)/ (γ P)

= √ (ρ_d)/ (ρ_m)

However, the presence of water vapour reduces the density of air, i.e.

(ρ_d) < (ρ_m)

Therefore, (v_m) > (v_d)

Hence, the speed of sound in moist air is greater than it is in dry air. Thus, in a gaseous medium, the speed of sound increases with humidity.

Video solution:

Waves Class 11 Physics NCERT Chapter 14 NCERT Solutions

Solving NCERT textbook questions of Waves Class 11 Physics NCERT Chapter 14 is a crucial step to gauge your understanding of the concepts. It provides you with an opportunity to assess your grasp of the material after learning each chapter. We have already provided solutions to all the exercises in the NCERT textbook of Class 11 Physics Waves, available in various formats such as video, text, and downloadable PDFs. If you need assistance with any of the NCERT questions or any other academic topics, feel free to ask in the “Ask Questions” section of LearnoHub.com.

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Attempt to Solve Yourself: Before looking at the solution, try to solve or answer the question independently. This practice will help you test your knowledge and problem-solving skills.
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Solve Again Yourself: Once you've understood the solution, attempt to solve the question again by yourself. Repetition and practice solidify your understanding of the concepts and improve retention.
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Attempt All Questions: Make an effort to attempt all the questions provided in the NCERT textbook. This comprehensive practice will help you cover the entire syllabus and reinforce your understanding across various topics. You may refer Class 11 Physics Waves Online Test on LearnoHub.com.
Review and Revise: Regularly review the concepts and solutions you've learned. Revise your notes and practice regularly to retain the knowledge effectively. You may refer Waves Class 11 Physics Notes.
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NCERT solutions of Waves Class 11 Physics - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 11 Physics Waves NCERT solutions.