NCERT solution Class 11 units and measurement

NCERT Solutions

Class 11 Physics

Units and Measurement

NCERT Questions

Q.1.1
Q.1.2
Q.1.3
Q.1.4
Q.1.5
Q.1.6
Q.1.7
Q.1.8
Q.1.9
Q.1.10
Q.1.11
Q.1.12
Q.1.13
Q.1.14
Q.1.15
Q.1.16
Q.1.17

Q.1.1

Fill in the blanks

(a) The volume of a cube of side 1 cm is equal to .....m³

(b) The surface area of a solid cylinder of radius 2.0 cm and height 10.0 cm is equal to ...(mm)²

(d) The relative density of lead is 11.3. Its density is ....g cm ^–3 or ....kg m^–³.

(a) Volume of cube = (a)³ (equation 1)

Length of edge 1cm= (1/100) m

Volume of cube = (1/100) m³

Using equation (1); 1cm x 1cm x 1cm

= (1/100) m x (1/100) m x (1/100) m

Therefore 1cm³ = 10^-6m³

Hence, the volume of a cube of side 1cm is equal to =10^-6m³.

(b) The total surface area of a cylinder of radius r and height h is: Given that:- r=2cm = (2x1) cm = (2x10) mm r=20mm h=10cm= (10 x 10) mm =100mm

Surface area of the cylinder S = 2 πr (h+r)

= (2x3.14x20x (20+100))

=15072

=1.5 x 10⁴(mm)²

Therefore, the surface area of a solid cylinder of radius 2.0cm and height 10.0cm is equal to =1.5 x 10⁴mm²

Speed s = 18 kmh^-1

Using, 1km = 1000m

1hour = 3600sec

Speed s = 18 x ( ) =

Therefore speed =

Distance = (speed x time) = 5 x 1 =5m.

Therefore, a vehicle moving with speed of 18kmh ^-1 covers 5m in 1s.

(d) Density of lead

= (Relative density of lead) x (Density of water)

Density of water =

= (11.3 x 1) = 11.3

Again, 1g = ( ) kg = ( ) kg

1cm³ = ( ) = ( ) m3

Therefore, =

= (11.3 x x ) kg

= (1.13 x ) kg

Therefore; the relative density of lead is 11.3. Its density is

11.3 g or 1.13 x kg

Video solution:

Units and Measurement Class 11 Physics NCERT Chapter 1 NCERT Solutions

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NCERT solutions of Units and Measurement Class 11 Physics - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 11 Physics Units and Measurement NCERT solutions.