NCERT solution Class 11 laws of motion

NCERT Solutions

Class 11 Physics

Laws of Motion

NCERT Questions

Q. 4.1
Q. 4.2
Q. 4.3
Q. 4.4
Q. 4.5
Q. 4.6
Q. 4.7
Q. 4.8
Q. 4.9
Q. 4.10
Q. 4.11
Q. 4.12
Q. 4.13
Q. 4.14
Q. 4.15
Q. 4.16
Q. 4.17
Q. 4.18
Q. 4.19
Q. 4.20
Q. 4.21
Q. 4.22
Q. 4.23

Q. 4.14

Figure 5.16 shows the position-time graph of a particle of mass 4 kg. What is the (a) force on the particle for t < 0, t > 4 s, 0 < t < 4 s? (b) Impulse at t = 0 and t = 4 s? (Consider one-dimensional motion only).

At t<0, the particle is not moving so no force will act on it. For t >4, x has constant value of 3m.Therefore as the body is at rest therefore no force acting on it.

During the interval 0<t<4, according to given figure the body is moving with constant speed. Therefore there will be no acceleration as velocity of the particle is constant.

For t>4s, in the given graph, we can see that the position of the particle is parallel to the time axis. This shows the particle is at rest at a distance of 3 m from the origin. Hence, no force is acting on the particle.

At t = 0

Impulse = Change in momentum

= (mv – mu)

Mass of the particle, m = 4 kg

Initial velocity of the particle, u = 0

Final velocity of the particle = m/s

Therefore, Impulse =4( -0) =3kgm/s

At t = 4 s

Before t=4s, particle has a constant velocity. u=0.75m/s

Initial velocity of the particle, u= m/s

After t=4s, particle is at rest, i.e.

Final velocity of the particle, v = 0

Therefore, Impulse =4(0- ) = -3kgm/s

Video solution:

Laws of Motion Class 11 Physics NCERT Chapter 4 NCERT Solutions

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NCERT solutions of Laws of Motion Class 11 Physics - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 11 Physics Laws of Motion NCERT solutions.