NCERT solution Class 11 kinetic theory

NCERT Solutions

Class 11 Physics

Kinetic Theory

NCERT Questions

Q. 12.1
Q. 12.2
Q. 12.3
Q. 12.4
Q. 12.5
Q. 12.6
Q. 12.7
Q. 12.8
Q. 12.9
Q. 12.10

Q. 12.5

An air bubble of volume 1.0 cm³ rises from the bottom of a lake 40 m deep at a temperature of 12 °C To what volume does it grow when it reaches the surface, which is at a temperature of 35 °C?

Given:

Volume of the air bubble, V₁ = 1.0 cm³ = (1.0 × 10^–6) m³

Bubble rises to height, d = 40 m

Temperature at a depth of 40 m, T₁ = 12°C = 285 K

Temperature at the surface of the lake, T₂ = 35°C = 308 K

The pressure on the surface of the lake:

P₂ = 1 atm = (1 ×1.013 × 10⁵) Pa

The pressure at the depth of 40 m:

P₁ = (1 atm + dρg)

Where, ρ is the density of water = 10³ kg/m³

g is the acceleration due to gravity = 9.8 m/s²

Therefore, P₁ = (1.013 × 10⁵ + 40 × 10³ × 9.8) = 493300 Pa

We have:

Where, V₂ is the volume of the air bubble when it reaches the surface

V₂ =

= (5.263 × 10^–6) m³ or 5.263 cm³

Therefore, when the air bubble reaches the surface, its volume becomes 5.263 cm³.

Video solution:

Kinetic Theory Class 11 Physics NCERT Chapter 12 NCERT Solutions

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NCERT solutions of Kinetic Theory Class 11 Physics - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 11 Physics Kinetic Theory NCERT solutions.