NCERT solution Class 11 sequences and series

NCERT Solutions

Class 11 Maths

Sequences and Series

NCERT Questions

Ex.9.1 Q.1
Ex.9.1 Q.2
Ex.9.1 Q.3
Ex.9.1 Q.4
Ex.9.1 Q.5
Ex.9.1 Q.6
Ex.9.1 Q.7
Ex.9.1 Q.8
Ex.9.1 Q.9
Ex.9.1 Q.10
Ex.9.1 Q.11
Ex.9.1 Q.12
Ex.9.1 Q.13
Ex.9.1 Q.14
Ex.9.2 Q.1
Ex.9.2 Q.2
Ex.9.2 Q.3
Ex.9.2 Q.4
Ex.9.2 Q.5
Ex.9.2 Q.6
Ex.9.2 Q.7
Ex.9.2 Q.8
Ex.9.2 Q.9
Ex.9.2 Q.10
Ex.9.2 Q.11
Ex.9.2 Q.12
Ex.9.2 Q.13
Ex.9.2 Q.14
Ex.9.2 Q.15
Ex.9.2 Q.16
Ex.9.2 Q.17
Ex.9.2 Q.18
Ex.9.3 Q.1
Ex.9.3 Q.2
Ex.9.3 Q.3
Ex.9.3 Q.4
Ex.9.3 Q.6
Ex.9.3 Q.6
Ex.9.3 Q.7
Ex.9.3 Q.8
Ex.9.3 Q.9
Ex.9.3 Q.10
Ex.9.3 Q.11
Ex.9.3 Q.12
Ex.9.3 Q.13
Ex.9.3 Q.14
Ex.9.3 Q.15
Ex.9.3 Q.16
Ex.9.3 Q.17
Ex.9.3 Q.18
Ex.9.3 Q.19
Ex.9.3 Q.20
Ex.9.3 Q.21
Ex.9.3 Q.22
Ex.9.3 Q.23
Ex.9.3 Q.24
Ex.9.3 Q.25
Ex.9.3 Q.26
Ex.9.3 Q.27
Ex.9.3 Q.28
Ex.9.3 Q.29
Ex.9.3 Q.30
Ex.9.3 Q.31
Ex.9.3 Q.32
Ex.9.4 Q.1
Ex.9.4 Q.2
Ex.9.4 Q.3
Ex.9.4 Q.4
Ex.9.4 Q.5
Ex.9.4 Q.6
Ex.9.4 Q.7
Ex.9.4 Q.8
Ex.9.4 Q.9
Ex.9.4 Q.10
Ex.Misc.Q.1
Ex.Misc.Q.2
Ex.Misc.Q.3
Ex.Misc.Q.4
Ex.Misc.Q.5
Ex.Misc.Q.6
Ex.Misc.Q.7
Ex.Misc.Q.8
Ex.Misc.Q.9
Ex.Misc.Q.10
Ex.Misc.Q.11
Ex.Misc.Q.12
Ex.Misc.Q.13
Ex.Misc.Q.14
Ex.Misc.Q.15
Ex.Misc.Q.16
Ex.Misc.Q.17
Ex.Misc.Q.18
Ex.Misc.Q.19
Ex.Misc.Q.20
Ex.Misc.Q.21
Ex.Misc.Q.22
Ex.Misc.Q.23
Ex.Misc.Q.24
Ex.Misc.Q.25
Ex.Misc.Q.26
Ex.Misc.Q.27
Ex.Misc.Q.28
Ex.Misc.Q.29
Ex.Misc.Q.30
Ex.Misc.Q.31
Ex.Misc.Q.32
Ex.15.2 Q.6
Ex.15.2 Q.7
Ex.15.2 Q.8
Ex.15.2 Q.9
Ex.15.2 Q.10
Ex.15.3 Q.1
Ex.15.3 Q.2
Ex.15.3 Q.3
Ex.15.3 Q.4
Ex.15.3 Q.5
Ex.Misc.Q.1
Ex.Misc.Q.2
Ex.Misc.Q.3
Ex.Misc.Q.4
Ex.Misc.Q.5
Ex.Misc.Q.6
Ex.Misc.Q.7

Ex.9.2 Q.16

Between 1 and 31, m numbers have been inserted in such a way that the resulting sequence is an A.P.

and the ratio of 7^th and (m – 1)^th numbers is 5: 9. Find the value of m.

Let A₁, A₂, ... A_m be m numbers such that 1, A₁, A₂, ... A_m, 31 is an A.P.

Here, a = 1, b = 31, n = m + 2

So, 31 = 1 + (m + 2 – 1) (d)

30 = (m + 1) d

d = 30 ÷ (m + 1) ………... (1)

A₁ = a + d

A₂ = a + 2d

A₃ = a + 3d

………………

A₇ = a + 7d

A_m–1 = a + (m – 1) d

According to the given condition,

(a + 7d) ÷ {a + (m - 1) d} =

=> [1 + 7{30 ÷ (m + 1)}] ÷ {1 + (m - 1) × (30 ÷ (m + 1))} =

[From equation 1]

=> [m + 1 + 7 × 30] ÷ [m + 1 + 30(m - 1)] =

=> [m + 1 + 210] ÷ [m + 1 + 30m - 30] =

=> [m + 211] ÷ [31m - 29] = 59

=> 9[m + 211] = 5[31m - 29]

=> 9m + 1899 = 155m - 145

=> 155m – 9m = 1899 + 145

=> 146m = 2044

=> m =

=> m = 14

Thus, the value of m is 14.

Video solution:

Sequences and Series Class 11 Maths NCERT Chapter 8 NCERT Solutions

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Attempt to Solve Yourself: Before looking at the solution, try to solve or answer the question independently. This practice will help you test your knowledge and problem-solving skills.
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Solve Again Yourself: Once you've understood the solution, attempt to solve the question again by yourself. Repetition and practice solidify your understanding of the concepts and improve retention.
Avoid Memorization: Focus on understanding the underlying principles and concepts behind each solution. Avoid simply memorizing the solutions, as this may hinder your ability to apply the knowledge in different contexts.
Attempt All Questions: Make an effort to attempt all the questions provided in the NCERT textbook. This comprehensive practice will help you cover the entire syllabus and reinforce your understanding across various topics. You may refer Class 11 Maths Sequences and Series Online Test on LearnoHub.com.
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NCERT solutions of Sequences and Series Class 11 Maths - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 11 Maths Sequences and Series NCERT solutions.