NCERT solution Class 11 relations and functions

NCERT Solutions

Class 11 Maths

Relations and Functions

NCERT Questions

Ex.2.1 Q,1
Ex.2.1 Q.2
Ex.2.1 Q.3
Ex.2.1 Q.4
Ex.2.1 Q.5
Ex.2.1 Q.6
Ex.2.1 Q.7
Ex.2.1 Q.8
Ex.2.1 Q.9
Ex.2.1 Q.10
Ex.2.2 Q.1
Ex.2.2 Q.2
Ex.2.2 Q.3
Ex.2.2 Q.4
Ex.2.2 Q.5
Ex.2.2 Q.6
Ex.2.2 Q.7
Ex.2.2 Q.8
Ex.2.2 Q.9
Ex.2.3 Q.1
Ex.2.3 Q.2
Ex.2.3 Q.3
Ex.2.3 Q.4
Ex.2.3 Q.5
Ex.Misc.Q.1
Ex.Misc.Q.2
Ex.Misc.Q.3
Ex.Misc.Q.4
Ex.Misc.Q.5
Ex.Misc.Q.6
Ex.Misc.Q.7
Ex.Misc.Q.8
Ex.Misc.Q.9
Ex.Misc.Q.10
Ex.Misc.Q.11
Ex.Misc.Q.12

Ex.2.1 Q.10

The Cartesian product A × A has 9 elements among which are found (–1, 0) and (0, 1).

Find the set A and the remaining elements of A × A.

We know that if n(A) = p and n(B) = q, then n (A × B) = pq.

So, n (A × A) = n(A) × n(A)

It is given that n (A × A) = 9

Hence, n(A) × n(A) = 9 => n(A) = 3

The ordered pairs (–1, 0) and (0, 1) are two of the nine elements of A × A.

We know that A × A = {(a, a): a ∈ A}. Therefore, –1, 0, and 1 are elements of A.

Since n(A) = 3, it is clear that A = {–1, 0, 1}.

The remaining elements of set A × A are

(–1, –1), (–1, 1), (0, –1), (0, 0), (1, –1), (1, 0), and (1, 1).

Video solution:

Relations and Functions Class 11 Maths NCERT Chapter 2 NCERT Solutions

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NCERT solutions of Relations and Functions Class 11 Maths - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 11 Maths Relations and Functions NCERT solutions.