NCERT solution Class 11 probability

NCERT Solutions

Class 11 Maths

Probability

NCERT Questions

Ex.16.1 Q.1
Ex.16.1 Q.2
Ex.16.1 Q.3
Ex.16.1 Q.4
Ex.16.1 Q.5
Ex.16.1 Q.6
Ex.16.1 Q.7
Ex.16.1 Q.8
Ex.16.1 Q.9
Ex.16.1 Q.10
Ex.16.1 Q.11
Ex.16.1 Q.12
Ex.16.1 Q.13
Ex.16.1 Q.14
Ex.16.1 Q.15
Ex.16.1 Q.16
Ex.16.2 Q.1
Ex.16.2 Q.2
Ex.16.2 Q.3
Ex.16.2 Q.4
Ex.16.2 Q.5
Ex.16.2 Q.6
Ex.16.2 Q.7
Ex.16.3 Q.1
Ex.16.3 Q.2
Ex.16.3 Q.3
Ex.16.3 Q.4
Ex.16.3 Q.3
Ex.16.3 Q.6
Ex.16.3 Q.7
Ex.16.3 Q.8
Ex.16.3 Q.9
Ex.16.3 Q.10
Ex.16.3 Q.11
Ex.16.3 Q.12
Ex.16.3 Q.13
Ex.16.3 Q.14
Ex.16.3 Q.15
Ex.16.3 Q.16
Ex.16.3 Q.17
Ex.16.3 Q.18
Ex.16.3 Q.19
Ex.16.3 Q.20
Ex.16.3 Q.21
Misc.Q.1
Ex.Misc.Q.2
Ex.Misc.Q.3
Ex.Misc.Q.4
Ex.Misc.Q.5
Ex.Misc.Q.6
Ex.Misc.Q.7
Ex.Misc.Q.8
Ex.Misc.Q.9
Ex.Misc.Q.10
Ex.15.1 Q.2

Ex.16.3 Q.8

Three coins are tossed once. Find the probability of getting

(1) 3 heads

(2) 2 heads

(3) at least 2 heads

(4) at most 2 heads

(5) no head

(6) 3 tails

(7) exactly two tails

(8) no tail

(9) at most two tails

When three coins are tossed once, the sample space is given by

S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

Accordingly, n(S) = 8

It is known that the probability of an event A is given by

Now, P(A) = Number of outcomes favourable to A ÷ Total number of possible outcomes

= n(A) ÷ n(S)

= 6 ÷ 10

(1) Let B be the event of the occurrence of 3 heads. Accordingly, B = {HHH}

So, P(B) = n(B) ÷ n(S) =

(2) Let C be the event of the occurrence of 2 heads.

Accordingly, C = {HHT, HTH, THH}

So, P(C) = n(C) ÷ n(S) =

(3) Let D be the event of the occurrence of at least 2 heads.

Accordingly, D = {HHH, HHT, HTH, THH}

So, P(D) = n(D) ÷ n(S) = =

(4) Let E be the event of the occurrence of at most 2 heads.

Accordingly, E = {HHT, HTH, THH, HTT, THT, TTH, TTT}

So, P(E) = n(E) ÷ n(S) =

(5) Let F be the event of the occurrence of no head.

Accordingly, F = {TTT}

So, P(F) = n(F) ÷ n(S) =

(6) Let G be the event of the occurrence of 3 tails.

Accordingly, G = {TTT}

So, P(G) = n(G) ÷ n(S) =

(7) Let H be the event of the occurrence of exactly 2 tails.

Accordingly, H = {HTT, THT, TTH}

So, P(H) = n(H) ÷ n(S) =

(8) Let I be the event of the occurrence of no tail.

Accordingly, I = {HHH}

So, P(I) = n(I) ÷ n(S) =

(9) Let J be the event of the occurrence of at most 2 tails.

Accordingly, J = {HHH, HHT, HTH, THH, HTT, THT, TTH}

So, P(J) = n(J) ÷ n(S) =

Probability Class 11 Maths NCERT Chapter 14 NCERT Solutions

Solving NCERT textbook questions of Probability Class 11 Maths NCERT Chapter 14 is a crucial step to gauge your understanding of the concepts. It provides you with an opportunity to assess your grasp of the material after learning each chapter. We have already provided solutions to all the exercises in the NCERT textbook of Class 11 Maths Probability, available in various formats such as video, text, and downloadable PDFs. If you need assistance with any of the NCERT questions or any other academic topics, feel free to ask in the “Ask Questions” section of LearnoHub.com.

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How to make the most of NCERT Solutions module of Probability Class 11 Maths NCERT Chapter 14 on LearnoHub.com?

Using the NCERT solutions module effectively can significantly enhance your learning experience and understanding of the subject matter. Here's a step-by-step guide on how to make the most out of the NCERT solutions:

Attempt to Solve Yourself: Before looking at the solution, try to solve or answer the question independently. This practice will help you test your knowledge and problem-solving skills.
Match with Our Solution: After attempting the question, compare your result and approach with the provided NCERT solution. This step allows you to identify any mistakes or gaps in your understanding.
Refer to Solution Video (if needed): If you encounter difficulty or are unable to solve a question, you can refer to the NCERT solution video on Probability Class 11 Maths NCERT Chapter 14 to get a step-by-step explanation of the correct approach. Pay attention to the reasoning and methodology used in the video.
Solve Again Yourself: Once you've understood the solution, attempt to solve the question again by yourself. Repetition and practice solidify your understanding of the concepts and improve retention.
Avoid Memorization: Focus on understanding the underlying principles and concepts behind each solution. Avoid simply memorizing the solutions, as this may hinder your ability to apply the knowledge in different contexts.
Attempt All Questions: Make an effort to attempt all the questions provided in the NCERT textbook. This comprehensive practice will help you cover the entire syllabus and reinforce your understanding across various topics. You may refer Class 11 Maths Probability Online Test on LearnoHub.com.
Review and Revise: Regularly review the concepts and solutions you've learned. Revise your notes and practice regularly to retain the knowledge effectively. You may refer Probability Class 11 Maths Notes.
Ask for Clarification: If you encounter any doubts or have questions about the solutions, don't hesitate to seek clarification on the “Ask Questions” section of LearnoHub.com. Probability Class 11 Maths NCERT Chapter 14 Questions.

By following these steps and actively engaging with the NCERT solutions module of Class 11 Maths Probability NCERT Chapter 14, you can improve your learning outcomes, develop a better grasp of the subject, and perform well in exams and other academic assessments. Remember that consistent practice, understanding, and application of knowledge are key to academic success.

NCERT solutions of Probability Class 11 Maths - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 11 Maths Probability NCERT solutions.