NCERT Solutions
Class 11 Maths
Probability

Ex.16.3 Q.3
A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed.
Find the probability that the sum of numbers that turn up is (1) 3 (2) 12
Since the fair coin has 1 marked on one face and 6 on the other, and the die has six faces that are numbered 1, 2, 3, 4, 5, and 6,
the sample space is given by:
S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
Accordingly, n(S) = 12
(1) Let A be the event in which the sum of numbers that turn up is 3.
So, A = {(1, 2)}
Now, P(A) = Number of outcomes favourable to A ÷ Total number of possible outcomes
= n(A) ÷ n(S)
=
(2) Let B be the event in which the sum of numbers that turn up is 12.
So, B = {(6, 6)}
Now, P(B) = Number of outcomes favourable to B ÷ Total number of possible outcomes
= n(B) ÷ n(S)
=