NCERT Solutions
Class 11 Maths
Linear Inequalities

Ex.Misc.Q.13
How many litres of water will have to be added to 1125 litres of the 45% solution of acid
so that the resulting mixture will contain more than 25% but less than 30% acid content?
Let amount of water is added = x litre
Given solution is 1125 litre
Percentage of acid in solution = 45%
So, percentage of water in solution = 55%
Case 1: Resulting mixture will contain more than 25% acid
x + 1125 × 55% = (x + 1125) × 75%
=> x + (1125 × 55) ÷ 100 = (x + 1125) × (75 ÷ 100)
=> 100x + 1125 × 55 = (x + 1125) × 75
=> 100x + 1125 × 55 = 75x + 1125 × 75
=> 100x - 75x = 1125 × 75 – 1125 × 55
=> 25x = 1125 × (75 - 55)
=> 25x = 1125 × 20
=> x = (1125 × 20) ÷ 25
=> x = (1125 × 4) ÷ 5
=> x = 225 × 4
=> x = 900
Case 2: Resulting mixture will contain more than 30% acid
x + 1125 × 55% = (x + 1125) × 70%
=> x + (1125 × 55) ÷ 100 = (x + 1125) × (70 ÷ 100)
=> 100x + 1125 × 55 = (x + 1125) × 70
=> 100x + 1125 × 55 = 70x + 1125 × 70
=> 100x - 70x = 1125 × 70 – 1125 × 55
=> 30x = 1125 × (70-55)
=> 30x = 1125 × 15
=> x = (1125 × 15) ÷ 30
=> x = (1125 × 5) ÷ 10
=> x = (1125) ÷ 2
=> x = 562.5
Now, 562.5 < x < 900
Thus, the required number of litres of water that is to be added will have to be more than 562.5 but less than 900.