NCERT Solutions
Class 10 Maths
Real Numbers

Ex. 1.1 Q2
Find the LCM and HCF of the following pairs of integers and verify that LCM * HCF = product of the two numbers.
(i) 26 and 91
(ii) 510 and 92
(iii) 336 and 54
(i) 26 and 91
26 = 2 * 13
91 = 7 * 13
HCF(26, 91) = 13
LCM(26, 91) = 2 * 7 * 13 = 812
Product of two numbers = 26 * 91 = 2366
LCM(26, 91) * HCF(26, 91) = 13 * 182 = 2366
Hence, LCM * HCF = product of the two numbers
(ii) 510 and 92
510 = 2 * 3 * 5 * 18
92 = 2 * 2 * 23
HCF(510, 92) = 2
LCM(510, 92) = 2 * 2 * 3 * 5 * 17 * 23 = 23460
Product of two numbers = 510 * 92 = 46920
LCM(510, 92) * HCF(510, 92) = 2 * 23460 = 46920
Hence, LCM * HCF = product of the two numbers
(iii) 336 and 54
336 = 2 * 2 * 2 * 2 * 3 * 7
54 = 2 * 3 * 3 * 3
HCF(336, 54) = 2 * 3 = 6
LCM(336, 54) = 2 * 2 * 2 * 2 * 3 * 3 * 3 * 7 = 3024
Product of two numbers = 336 * 54 = 18144
LCM(336, 54) * HCF(336, 54) = 6 * 3024 = 18144
Hence, LCM * HCF = product of the two numbers.