NCERT Solutions
Class 10 Maths
Polynomials

Ex. 2.2 Q2
Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.
(i) 1/4, -1
(ii) √2, 1/3
(iii) 0, √5
(iv) 1, 1
(v) -1/4, 1/4
(vi) 4, 1
(i) Let α and β are the zeroes of the quadratic polynomial ax2 + bx + c.
Given, α + β = 1/4 = -b/a
and α * β = -1 = -4/4 = c/a
On comparing, we get
a = 4, b = -1, c = -4
Hence, the required quadratic polynomial is 4x2 - x - 4.
(ii) Let α and β are the zeroes of the quadratic polynomial ax2 + bx + c.
Given, α + β = √2= 3√2/3 = -b/a
and α * β = 1/3 = c/a
On comparing, we get
a = 3, b = -3√2, c = 1
Hence, the required quadratic polynomial is 3x2 - 3√2x + 1.
(iii) Let α and β are the zeroes of the quadratic polynomial ax2 + bx + c.
Given, α + β = 0 = 0/1 = -b/a
and α * β = √5 = √5/1 = c/a
On comparing, we get
a = 1, b = 0, c = √5
Hence, the required quadratic polynomial is x2 – 0*x + √5 = x2 + √5.
(iv) Let α and β are the zeroes of the quadratic polynomial ax2 + bx + c.
Given, α + β = 1 = 1/1 = -b/a
and α * β = 1 = 1/1 = c/a
On comparing, we get
a = 1, b = -1, c = 1
Hence, the required quadratic polynomial is x2 - x + 1.
(v) Let α and β are the zeroes of the quadratic polynomial ax2 + bx + c.
Given, α + β = -1/4 = -b/a
and α * β = 1/4 = c/a
On comparing, we get
a = 4, b = 1, c = 1
Hence, the required quadratic polynomial is 4x2 + x + 1.
(vi) Let α and β are the zeroes of the quadratic polynomial ax2 + bx + c.
Given, α + β = 4 = 4/1 = -b/a
and α * β = 1 = 1/1 = c/a
On comparing, we get
a = 1, b = -4, c = 1
Hence, the required quadratic polynomial is x2 - 4x + 1.