NCERT solution Class 10 constructions

NCERT Solutions

Class 10 Maths

Constructions

NCERT Questions

Ex.11.1 Q.1
Ex.11.1 Q.2
Ex.11.1 Q.3
Ex.11.1 Q.4
Ex.11.1 Q.5
Ex.11.1 Q.6
Ex.11.1 Q.7
Ex.11.2 Q.1
Ex.11.2 Q.2
Ex.11.2 Q.3
Ex.11.2 Q.4
Ex.11.2 Q.5
Ex.11.2 Q.6
Ex.11.2 Q.7

Ex.11.2 Q.1

Draw a circle of radius 6 cm. From a point 10 cm away from its centre,

construct the pair of tangents to the circle and measure their lengths.

Give the justification of the construction.

A pair of tangents to the given circle can be constructed as follows:

Step 1. Taking any point O of the given plane as centre, draw a circle of 6 cm radius. Locate a

point P, 10 cm away from O. Join OP.

Step 2. Bisect OP. Let M be the mid-point of PO.

Step 3. Taking M as centre and MO as radius, draw a circle.

Step 4. Let this circle intersect the previous circle at point Q and R.

Step 5. Join PQ and PR. PQ and PR are the required tangents.

The lengths of tangents PQ and PR are 8 cm each.

Justification:

The construction can be justified by proving that PQ and PR are the tangents to the circle (whose centre is O and radius is 6 cm).

For this, join OQ and OR.

∠PQO is an angle in the semi-circle. We know that angle in a semi-circle is a right angle.

So, ∠PQO = 90⁰

=> OQ ⊥ PQ

Since OQ is the radius of the circle, PQ has to be a tangent of the circle.

Similarly, PR is a tangent of the circle.

Video solution:

Constructions Class 10 Maths NCERT Chapter 11 NCERT Solutions

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NCERT solutions of Constructions Class 10 Maths - all questions of all exercises are solved. Q. No. 1, 2, 3, and so on. Complete explanation and detailed solution makes them the best videos for Class 10 Maths Constructions NCERT solutions.