NCERT Solutions
Class 10 Maths
Areas Related to Circles

Ex.11.1 Q.13
A round table cover has six equal designs as shown in Fig. 12.14. If the radius of the cover is 28 cm, find the cost of making the designs at the rate of Rs 0.35 per cm2. (Use √3 = 1.7)
Here, r = 28 cm
Since, the circle is divided into six equal sectors.
So, sector angle θ = 360° ÷ 6 = 60°
Area of the sector with angle 60° and radius 28 cm = (θ ÷ 360°) × πr2
= (60° ÷ 360°) × ( ) × 28 × 28
= ( ) x
× 28 × 4
= (44 × 28) ÷ 3
=
= 410.67 cm2 …………… (1)
Now, area of 1 design = Area of segment APB
= Area of sector – Area of ΔAOB …………... (2)
In ΔAOB, ∠AOB = 60°, OA = PN = 28 cm
So, ∠OAB = 60° and ∠OBA = 60°
=> ΔAOB is an equilateral triangle.
=> AB = AO = BO
=> AB = 28 cm
=> Draw OM ⊥AB
Now, in right ΔAOM, we have
= sin 60° =
=> OM = OA ×
=> OM = 28 ×
=> OM = 14√3 cm
Area of ΔAOB = × AB × OM
= × 28 × 14√3
= 14 × 14 × 1.7
= 333.3 cm2 ………... (3)
Now, from (1), (2) and (3), we have:
Area of segment APQ = 410.67 – 333.2
= 77.47 cm2
=> Area of 1 design = 77.47 cm2
So, area of the 6 equal designs = 6 × 77.47
= 464.82 cm2
Cost of making the design at the rate of Rs. 0.35 per cm2 = Rs. 0.35 × 464.82
= Rs. 162.68