Daily Practice Problems
NEET Chemistry
Thermodynamics
daily practice problem

Question 1.

Which of the following statement obeyed third law of thermodynamics?

[Level: Moderate]

(a) The entropy of 1 mole of solid HCl at 0K is zero while entropy of one mole of solid CO is 5J/K.

(b) Entropy of an isolated system can never decrease over time

(c) Conservation of energy

(d) None of these

 

Question 2.

At equilibrium, value of free energy change is  [Level: Easy]

(a) +ve

(b) -ve

(c) zero

(d) A & B both

 

Question 3.

Equilibrium constant for a reaction is e-2then ∆G0 is  – [Level: Moderate]

(a) -2 J/Mol

(b) 2 J/Mol

(c) -4.606 J/Mol

(d) e J/Mol

 

Question 4.

Calculate W and ∆E for the conversion of 1 mole of water into 1 Mole of steam at a temperature of 1000C and at a pressure of 1 atmosphere latent heat of vaporisation of water is 9720 cal/mol. [Level: Difficult]

(a) 8979 cal

(b) 8000 cal

(c) 89.2 KJ

(d) 90 J

 

Question 5.

The net internal energy change in reversible cyclic process is –[Level: Difficult]

(a)  RT

(b) Zero

(c) Greater than zero

(d) Less than Zero

 

Question 6.

Calculate the temperature at which 32g of O2 will occupy a volume of 10.0 L at 3.16 atm. [Level: Easy]

(a) 273.1k

(b) 384.8K

(c) 348.6K

(d) 1170C

 

Question 6.

During a thermodynamic process, 93 KJ of heat flows into the system and work done by the system is 47KJ. The increase in internal energy of the system is  – [Level: Moderate]

(a) Ammonia < Methane

(b) Ammonia > Methane

(c) +52KJ

(d) Diffusion will not take place

 

Question 7.

If the standard enthalpies of formation (∆H0f) for CO2, CO, H2O are -453.5,-217.3 and -141.8 KJmol-1respectively than what will be the change in enthalpy for the reaction – [Level: Easy]

(a) +194.4kJ

(b) +94.4kJ

(c) +84.4kJ

(d) -94.4kJ

 

Question 8.

Plants and living being are the example of –

(a) Adiabatic system

(b) Isolated system

(c) Open system

(d) Closed system

 

Question 9.

In a fuel cell (Device used for producing electricity directly from a chemical reaction) methanol is used as fuel and oxygen gas is used as an oxidizer. The standard enthalpy of combustion of methanol is -726 KJmol-1. The standard free enthalpy of formation of CH3OH(l),CO2(g) and H2O(l) are -126.3,-434.4 and -257.1 KJmol-1 Respectively then find the standard free energy for the reaction. [Level: Moderate]

(a) 9 dm3

(b) 3 dm3

(c) 4 dm3

(d) 5 dm3

 

Question 10.

The efficiency of the fuel cell will be:

(Hint: Use value of standard free energy from Q.9)  [Level: Easy]

(a) 96.7%

(b) 66.2%

(c) 41.3%

(d) 85.1%

 

Question 11.

29 ml of pure water takes 90 sec to evaporate from a vessel and heater connected to an electric source which delivers 716 watt. The ∆Hvap of water is: –[Level: Moderate]

(a) 40.000 KJ/m Approx  

(b) 40000 J/m Approx

(c) 31.901 KJ/m Approx

(d) 45.104 KJ/m Approx

 

Question 12.

Calculate the work performed when 3 moles of hydrogen expand isothermally and reversibly at 270C from 35 to 70 L – [Level: Moderate]

(a) - 1247.7 cal

(b) - 1247.7 erg

(c) – 12.47 cal

(d) - 1247.7 J

 

Question 13.

4 mole of NH3(Υ = 1.33)  gas at 307K is expanded under adiabatic condition to increase the volume 0.5 times then what will be the temperature and the value of work done – [Level: Difficult]

(a) T2 = 614, W= -1.268

(b) T2 = 614, W= -7008

(c) T2 = 641, W= -8765

(d) T2 = 146, W= -1308

 

Question 14.

Five moles of gas is put through a series of changes as shown graphically in cycle process

The process AàB, B àC and CàA are respectively [Level: Easy]

 

 

 

 

 

 

 

 

(a) Isochoric, Isobaric, Isothermal

(b) Isobaric, Isochoric, Isothermal

(c) Isochoric, Isothermal, Isobaric

(d) Isobaric, Isothermal, Isochoric

 

Question 15.

For the gas phase reaction:

PCl5 ⇌ PCl3 + Cl2

Which of the following conditions are correct [Level: Moderate]

(a) ∆H < 0, ∆S < 0

(b) ∆H > 0, ∆S < 0

(c) ∆H = 0, ∆S < 0

(d) ∆H > 0, ∆S > 0

 

Question 16.

Find ∆Sf0 at 250C for PCl5(g) If ∆Hf0 is -396.9 KJ/mole and ∆G0f is -315 KJ/mol.  [Level: Easy]

(a) ∆S0 = -0.274.8 KJ/mol K

(b) ∆S0 = -274.8 J/mol K

(c) ∆S0 = -274.8 x 107 erg/mol K

(d) All of these

 

Question 17.

What will be the pressure of 5 mol of an ideal gas at 314K having volume 11.8 L? [Level: Easy]

(a) 1 atm

(b) 2.12 atm

(c) 9.0 atm

(d) 11 atm

 

Question 18.

Calculate the entropy change involved in the conversion of one mole of water at 396K to vapour at the same temperature. (Latent heat of vaporization of Water = 2.257KJg-1) : [Level: Easy]

(a) ∆SV = 102.5JK-1Mol-1

(b) ∆SV = 11.5JK-1Mol-1

(c) ∆SV = 10.5JK-1Mol-1

(d) ∆SV = 201.5JK-1Mol-1

 

Question 19.

Calculate ∆H at 457K for reaction

Fe2O3(S) + 3H2(g) à 2Fe + 3H2O(l)

Given that ∆H298 = -33.29 Kj Mol-1 and Cp for Fe2O3(s), Fe(s), H2O(l) and H2(g) are 98.8, 29.1, 64.3 and 18.7 J/K mole

(a) -18.3291 KJ/mol

(b) -183291 KJ/mol

(c) 18.3291 KJ/mol

(d) 18.3291 J/mol

 

Question 20.

At a given temperature, the energy of activation of two reaction is same if [Level: Easy]

(a) The specific rate constant for the two reaction is the same

(b) The temperature coefficient for the specific rate constant for the two reaction is same

(c) ∆H for the two reaction is the same but not Zero

(d) ∆H for the two reactant is zero

**********

 

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  1. Application of Knowledge: Problem-solving allows you to apply the theoretical concepts of the topic NEET Chemistry Thermodynamics you have learned to real-life situations. It helps you bridge the gap between abstract knowledge and practical scenarios, making the learning more relevant and meaningful.
  2. Understanding Deeper Concepts: When you encounter problems related to a theoretical concept that you learned in NEET Chemistry Thermodynamics NCERT Chapter 6, you are forced to delve deeper into its intricacies. This deeper understanding enhances your comprehension of the subject and strengthens your grasp of the underlying principles.
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  4. Retention and Recall: Actively engaging in problem-solving reinforces your memory and improves long-term retention. Applying the concepts learned in Thermodynamics NEET Chemistry in practical scenarios helps you remember them better than passive reading or memorization.
  5. Identifying Knowledge Gaps: When you attempt to solve problems, you may encounter areas where your understanding is lacking. These knowledge gaps become evident during problem-solving, and you can then focus on filling those gaps through further study and practice. You can refer Thermodynamics NEET Chemistry Notes on LearnoHub.com
  6. Boosting Confidence: Successfully solving problems after learning a theoretical concept boosts your confidence in your abilities to handle Thermodynamics. This confidence motivates you to tackle more challenging tasks and improves your overall performance in the subject.
  7. Preparation for Exams and Challenges: Many exams, especially in science, mathematics, and engineering, involve problem-solving tasks. Regular practice in problem-solving prepares you to face these exams with confidence and perform well. It is also advised to take tests on Thermodynamics NEET Chemistry Online Tests at LearnoHub.com.
  8. Enhancing Creativity: Problem-solving often requires thinking outside the box and exploring various approaches. This fosters creativity and innovation, enabling you to come up with novel solutions to different problems.
  9. Life Skills Development: Problem-solving is a valuable life skill that extends beyond academics. It equips you with the ability to tackle various challenges you may encounter in personal and professional life.
  10. Improving Decision Making: Problem-solving involves making decisions based on available information and logical reasoning. Practicing problem-solving enhances your decision-making skills, making you more effective in making informed choices.

In summary, problem-solving after learning a theoretical concept on CBSE Thermodynamics NEET Chemistry is an essential part of the learning process. It enhances your understanding, critical thinking abilities, and retention of knowledge. Moreover, it equips you with valuable skills that are applicable in academic, personal, and professional contexts.

You must have heard of the phrase “Practice makes a man perfect”. Well, not just a man, practice indeed enhances perfection of every individual.

Practicing questions plays a pivotal role in achieving excellence in exams. Just as the adage goes, "Practice makes perfect," dedicating time to solve a diverse range of exam-related questions yields manifold benefits. Firstly, practicing questions allows students to familiarize themselves with the exam format and types of problems they might encounter. This familiarity instills confidence, reducing anxiety and improving performance on the actual exam day. Secondly, continuous practice sharpens problem-solving skills and enhances critical thinking, enabling students to approach complex problems with clarity and efficiency. Thirdly, it aids in identifying weak areas, allowing students to focus their efforts on improving specific topics. Moreover, practice aids in memory retention, as active engagement with the material reinforces learning. Regular practice also hones time management skills, ensuring that students can allocate appropriate time to each question during the exam. Overall, practicing questions not only boosts exam performance but also instills a deeper understanding of the subject matter, fostering a holistic and effective learning experience.

All About Daily Practice Problems on NEET Chemistry Thermodynamics NCERT Chapter 6

Our Daily Practice Problems (DPPs) offer a diverse range of question types, including Multiple Choice Questions (MCQs) as well as short and long answer types. These questions are categorized into Easy, Moderate, and Difficult levels, allowing students to gradually progress and challenge themselves accordingly. Additionally, comprehensive solutions are provided for each question, available for download in PDF format - Download pdf solutions as well as Download pdf Questions. This approach fosters a holistic learning experience, catering to different learning styles, promoting self-assessment, and improving problem-solving skills. With our well-structured DPPs, students can excel in exams while gaining a deeper understanding of the subject matter. Hope you found the content on NEET Chemistry Thermodynamics NCERT Chapter 6 useful.

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