Question:
a tank contains a transparent liquid a refracted n the bottom of which is made up of a mirror . an object o lies at a height of D above the mirror a person P vertically above the object is O and its image in the mirror and finds the appearant separation to be
Answer:
The image of P will be formed at a distance h below the mirror.
Apparent depth of P is x1 = [(d – h) / n]
Apparent depth of P is x2 = [(d + h) / n]
Apparent distance between P and its image = x2 – x1 = [(d + h) / n] – [(d – h) / n] = [(d + h – d + h) / n] = (2h / n).
Not what you are looking for? Go ahead and submit the question, we will get back to you.
