Question:
The science lecture theatre of a colleges 10 m wide and has a door at at a corner A science teacher enters at 12 o'clock noon through the door and makes 8 round along the 10 m wall back and forth during the period and finally leave the classroom at 12:40 p m to the same door Compute the average speed and average velocity
Answer:
Width = 10 m
Lecturer makes 8 rounds back and forth
so Distance covered = 8 * ( 10 + 10) = 160 m
Time = 40 m
Average Speed = Total Distance / Total Time = 160/40
= 4 m/s
Average Velocity = Total Displacement / Total Time
As Lecturer entered from door & left from door so
Total displacement = 0
Average Velocity = 0/40 = 0 m/s
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