Question:
A monkey of mass 10root3 kg is climbing up the corner formed by two intersections of two vertical perpendicular walls The coefficient of friction is sqqure root 2 The minimum force with which the monkey had to push on the walls while climbing is -----
Answer:
The net force in the horizontal direction is zero as well, as the monkey is not accelerating horizontally. Therefore, the frictional force (f) and the horizontal force (F) are equal in magnitude.
We have: f = F
Substitute f = μmg:
F = μmg
Now, plug in the given values:
F = (√2) * (10√3 kg) * (9.81 m/s²)
Calculate the value of F to find the minimum force required for the monkey to climb up the corner while pushing on the walls.
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