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Question:

compound interest for 3000 at 10% and years 3

Answer:

Given

P=Rs3000

r=10%

n=3 years

Amount ,A = P(1+(r/100))ⁿ

^{A = 3000(1+(10/100))^3}

^{A=Rs 3993}

^A=P+C.I

^C.I=A-P

^=3993-3000

^{Rs 993}

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