Question:
The side of the triangle are 12cm, 16cm and 20cm. It's area is
Answer:
Area of a triangle of sides a , b & c is given as
A = √[s(s - a)(s - b)(s - c)]
where s = (a + b + c)/2
ln given trangle , s = (20 + 12 + 16)/2 = 48/2 = 24
Thus area of given triangle = √[24(24 - 20)(24 - 12)(24 - 16)]
= √(24 × 4 × 12 × 8)
= √9216
= 96
Thus, the area of triangle of sides 12 cm, 16 cm and 20 cm is 96 cm2.
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