Given, ABCD is a parallelogram in which AO and OB are angle bisector of A and B

So, AD || BC   {Since ABCD is a parallelogram}

Again, AD || BC and traversal AB intersect them,

So, ∠A + ∠B = 180  {sum of interior angle is 180 degree}

=> ∠A/2 + ∠B/2 = 180/2

=> ∠A/2 + ∠B/2 = 90

=> ∠1 + ∠2 = 90

So, AO and OB are angle bisectors

Now, in triangle AOB,

∠1 + ∠AOB + ∠2 = 180

=> 90 + ∠AOB = 180

=> ∠AOB = 180 - 90

=> ∠AOB = 90

=> ∠x = 90

So, the value of x is 90 degree