Question:
In a kite ABCD, AB=AD and BC =DC, if angle A=80, angle B=40 then find angle C and angle D
Answer:
Given, ABCD is a kite.
Again, AB = AD and BD = BC
Now, in a kite,
∠A + ∠B + ∠C + ∠D = 180
=> 80 + 40 + ∠C + ∠D = 180
=> 120 + ∠C + ∠D = 180
=> ∠C + ∠D = 180 - 120
=> ∠C + ∠D = 60
Since, ∠C = ∠D
So, ∠C + ∠C = 60
=> 2∠C = 60
=> ∠C = 60/2
=> ∠C = 30
Hence, ∠C = ∠D = 60 degree
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