


Let AC and BD are the diagonal of the parallelogram.
Here, AC = 12 cm, BD = 16 cm
Now, AC and BD bisect each other ate right angle at the point O.
Now, OB = BD/2 = 16/2 = 8
OA = AC/2 = 12/2 = 6
and ∠AOB = 90
From triangle AOB
Using Pytahgorus Theorem,
AB2 = OB2 + OA2
=> AB2 = 82 + 62
=> AB2 = 64 + 36
=> AB2 = 100
=> AB = √100
=> AB = 10 cm
Similarly, From triangle COB, COD and AOD,
the length of BC, CD, and AD is equal to 10 cm each.
Now, perimeter = 2(10 + 10) = 2*20 = 40 cm
