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Correct question is:
If 2 is a square root of 4 then what is the square root of 128
Solution:
Given √4 = 2
=> √(2 * 2) = 2
Now, √128 = √(2*2*2*2*2*2*2)
=> √128 = 2 * 2 * 2 * √2
=> √128 = 8√2
So, the square root of 128 is 8√2