Question:
if the 2/5 of a number exceeds 1/7 of the same number by 36.find the number
Answer:
Let the number is x
Given, 2/5 of a number exceeds 1/7 of the same number by 36
=> 2x/5 = x/7 + 36
=> 2x/5 - x/7 = 36
=> (2x * 7 - 5x)/35 = 36 {LCM of 5 and 7 is 35}
=> (14x - 5x)/35 = 36
=> 9x/35 = 36
=> 9x = 36*35
=> x = (36*35)/9
=> x = 4*35 {36 and 9 is divided by 9}
=> x = 140
So, the number is 140
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