


We know that in an equilateral triangle, all sides are equal in length.
So, AB = BC = CA
Given, O is on the side AB
So, AO < AB
=> AO < AC ...........1 {since AB = AB}
and CO is the line formed by joining C to the point O and O is no AB
Again, ∠CAO = ∠CBO = ∠ACB {angles are same in equilateral triangle}
Again given, ∠ACB is split side by side CO
So, ∠ACO < ∠CAO
Again, we know that side opposite to greater angle is longer
So, CO > AO ..........2
Now, from equation 1 and 2, we get
CO must be smaller than AC or AB
Hence, decreasing order is:
AC > CO > AO
