learnohub
Question:
Construct a parallelogram ABCD in which side BC=5.6 cm and diagonals AC=6.2 cm and BD=8 cm.
Answer:

Let AC and BD are the diagonal of the parallelogram which intersects each other at point O.

Now, AO = OC = AC/2 = 6.2/2 = 3.1

And BO = OD = BD/2 = 8/2 = 4

Construction:

1. Draw a line segment BC of length 5.6 cm

2. Now, take B as center and draw an arc length of 4 cm

3. Again, take C as center and draw an arc length of 3.1 cm which intersect the previous arc at point O

4. Now, join O to B and C

5. Extend BO to D such that BD = 8

6. Extend CO to A such that AC = 6.2

7. Finally, join A to B, A to D and C to D.

This is the required parallelogram ABCD

 

Not what you are looking for? Go ahead and submit the question, we will get back to you.

learnohub

Classes

  • Class 6
  • Class 7
  • Class 8
  • Class 9
  • Class 10
  • Class 11
  • Class 12
  • ICSE 6
  • ICSE 7
  • ICSE 8
  • ICSE 9
  • ICSE 10
  • NEET
  • JEE

YouTube Channels

  • LearnoHub Class 11,12
  • LearnoHub Class 9,10
  • LearnoHub Class 6,7,8
  • LearnoHub Kids

Overview

  • FAQs
  • Privacy Policy
  • Terms & Conditions
  • About Us
  • NGO School
  • Contribute
  • Jobs @ LearnoHub
  • Success Stories
© Learnohub 2026.