Question:
find the two parallel sides of a trapezium whose area is 1.6 m altitude is 10 dm and one of the parallel sides is longer than the other by 8 dm
Answer:
Given area of trapezium = 1.6 sq m
Altitude, h = 10 dm = 1 m
Let one of the parallel sides be x then the other side will be (x + 0.8) m
Recall that area of trapezium, A = (1/2) * h * (a + b)
=> 1.6 = (1/2) * 1 * (x + x + 0.8)
=> 1.6 * 2 = x + x + 0.8)
=> 3.2 = 2x + 0.8
=> 2x = 3.2 - 0.8 = 2.4
Therefore, x = 1.2 m
and x + 0.8 = 1.2 + 0.8 = 2 m
Thus, the parallel sides are 1.2 m and 2 m
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