Question:
Find the courved Surface area of a garden roller whose length and diameter are 1.5m and 1.4 m respectively . how much area can it level in 200 revolutions
Answer:
Given, length of the garden roller = 1.5 m
and diameter of the garden roller = 1.4 m
So, radius of the garden roller = 1. 4/2 = 0.7 m
Now, curved surface are of the roller = curved surface are of the cylinder
= 2πrh
= 2 *(22/7) * 0.7 * 1.5
= 2 * 22 * 0.1 * 1.5
= 6.6 m2
Now, in one revolution, area covered by roller = 6.6 m2
So, in 200 revolutions, area covered by roller = 6.6 * 200 = 1320.0 m2
Not what you are looking for? Go ahead and submit the question, we will get back to you.
