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Given, (x - 5)/2 - (x - 3)/5 = 1
=> {5(x - 5) - 2(x - 3)}/10 = 1 { LCM(2, 5) = 10 }
=> {5(x - 5) - 2(x - 3)} = 10
=> (5x - 25) - (2x - 6) = 10
=> 5x - 25 - 2x + 6 = 10
=> 3x - 19 = 10
=> 3x = 10 + 19
=> 3x = 29
=> x = 29/3
So, the value of x is 29/3