Question:
the length of a rectangle is 1 more than twice its breadth.if the perimeter of the rectangle is 44cm,find its dimensions
Answer:
Let breadth of the rectangle = b
So, length of the rectangle = 2b + 1
Given, perimeter of the rectangle = 44
=> 2*(length + breadth) = 44
=> 2*(2b + 1 + b) = 44
=> 2*(3b + 1) = 44
=> 3b + 1 = 44/2
=> 3b + 1 = 22
=> 3b = 22 - 1
=> 3b = 21
=> b = 21/3
=> b = 7
So, breadth of the rectangle = b = 7 cm
and length of the rectangle = 2b + 1 = 2*7 + 1 = 15 cm
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