Question:
ronit is now 32 years old and his son is 7 years old.in how many years will ronit be twice as old as his son
Answer:
Given, age of Ronit = 32 years
and age of his son = 7 years
Let after x years, age of Ronit will be twice of his son.
So, x + 32 = 2(7 + x)
=> x + 32 = 14 + 2x
=> 2x - x = 32 - 14
=> x = 18
So, after 18 years, age of Ronit will be twicw of his son.
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