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Given, x/2 - 1/5 = x/3 + 1/4
=> x/2 = x/3 + 1/4 + 1/5
=> x/2 - x/3 = 1/4 + 1/5
=> (3x - 2x)/6 = (5 + 4)/20 { LCM(2, 3) = 6 and LCM(4, 5) = 20 }
=> x/6 = 9/20
By cross multiplication, we get
=> 20x = 9*6
=> 20x = 54
=> 20 x - 54 = 0