Question:
9x²y² - 16
Answer:
Given, 9x²y² - 16
= (3xy)2 - 42
= (3xy - 4)*(3xy + 4) [since a2 - b2 = (a - b)*(a + b)]
So, 9x²y² - 16 = (3xy - 4)*(3xy + 4)
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Given, 9x²y² - 16
= (3xy)2 - 42
= (3xy - 4)*(3xy + 4) [since a2 - b2 = (a - b)*(a + b)]
So, 9x²y² - 16 = (3xy - 4)*(3xy + 4)