

Given √x = 3√9
=> (x)1/2 = (9)1/3
=> (x)1/2 = (32 )1/3
=> (x)1/2 = (3)2/3
Now squaring on both side, we get
{(x)1/2 }2 = {(3)2/3 }2
=> (x)(1*2)/2 = (3)(2*2)/3
=> (x)2/2 = (3)4/3
=> x = (3)4/3
=> x = (34 )1/3
=> x = (81)1/3
=> x = 3√81
=> x = 3√(3*3*3*3)
=> x =3* 3√3
