Question:
a man is 28 years older than his son. after 10 years , he will be thrice as old as his son .find their present ages.
Answer:
Let present age of son = x years
So, present age of father = x + 28 years,
After 10 years,
Age of son = x + 10 years
and age of father = x + 28 + 10 = x + 38 years,
Given that, after 10 years, age of father will be thrice as old as his son
=> x + 38 = 3(x + 10)
=> x + 38 = 3x + 30
=> 38 = 3x + 30 - x
=> 38 = 2x + 30
=> 2x = 38 - 30
=> 2x = 8
=> x = 8/2
=> x = 4
So, present age of son = x = 4 years
and present age of father = x + 28 = 4 + 28 = 32 years,
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