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Question:
from a rope 11m long,two pieces of lenghts 13/5 and 33/10 are cut off what is the lenght of the remaining rope
Answer:

Given, total length of the rope = 11 m

Now, two pieces of lengths 13/5 and 33/10 are cut off 

The length of the remaining rope = 11 - (13/5 + 33/10)

                                                     = 11 - {13 * 2 + 33)/10}      {LCM(5, 10) = 10}

                                                     = 11 - (26 + 33)/10

                                                     = 11 - 59/10

                                                     = (11 * 10 - 59)/10

                                                     = (110 - 59)/10

                                                     = 51/10 m

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