

Let r is the radius of the circular sheet.
Given perimeter of the circular sheet = 154
=> 2πr = 154
=> 2 *(22/7)*r = 154
=> 44r/7 = 154
=> 44r = 154*7
=> r = (154*7)/44
=> r = (77*7)/22 {154 and 44 is divided by 2}
=> r = (7*7)/2 {77 and 22 is divided by 11}
=> r = 49/2
=> r = 24.5 m
So, the radius is 24.5 m
Now, area of the circular sheet = πr2 = (22/7)*(49/2)2
= (22/7)*(49/2)*(49/2)
= (11/7)*(49)*(49/2)
= (11*7*49)/2
= 3773/2
= 1886.5 m2
So, the area is 1886.5 m2
